Question

a sealable bag holds 3.79 l of gas. how many moles of h₂ gas are needed to fill the bag at 1.0 atm and 293 k? ? mol h₂ hint: use pv = nrt.

Explanation:

Step1: List known values

\(P=1.0\ \text{atm}\), \(V=3.79\ \text{L}\), \(R=0.0821\ \frac{\text{L·atm}}{\text{mol·K}}\), \(T=293\ \text{K}\)

Step2: Rearrange ideal gas law for \(n\)

\(n=\frac{PV}{RT}\)

Step3: Calculate moles of \(H_2\)

\(n=\frac{1.0\times3.79}{0.0821\times293}=\frac{3.79}{24.0553}\approx0.158\)

Answer:

0.16 (rounded to two decimal places) or 0.158 (unrounded)