Question

a sample of neon gas at 1.20 atm expands from 0.125 l to 0.250 l. if the temperature remains constant, what is the final pressure in atm? 0.600 atm 1.60 atm 1.200 atm 0.800 atm 1.912 atm

Explanation:

Step1: Identify the formula

Boyle's Law: \(P_1V_1 = P_2V_2\) (temperature is constant).

Step2: Rearrange the formula for \(P_2\)

\(P_2=\frac{P_1V_1}{V_2}\)

Step3: Substitute the values

Given \(P_1 = 1.20\) atm, \(V_1=0.125\) L, \(V_2 = 0.250\) L.
\(P_2=\frac{1.20\times0.125}{0.250}\)
\(P_2=\frac{0.15}{0.250}=0.600\) atm

Answer:

0.600 atm