Question

a sample of hexane (c₆h₁₄) has a mass of 0.580 g. the sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a specific heat of 3.21 j/g·k. what amount of heat is produced during the combustion of hexane if the temperature of the calorimeter increases by 4.542 k? use q = mcₚδt. 8.46 kj 16.1 kj 27.7 kj 47.8 kj

Explanation:

Step1: Identify given values

Mass of calorimeter \( m = 1.900\space kg = 1900\space g \), specific heat \( C_p = 3.21\space J/g\cdot K \), temperature change \( \Delta T = 4.542\space K \).

Step2: Apply the formula \( q = mC_p\Delta T \)

Substitute the values into the formula:
\( q = 1900\space g \times 3.21\space J/g\cdot K \times 4.542\space K \)

Step3: Calculate the product

First, multiply \( 1900 \times 3.21 = 6099 \). Then, multiply by \( 4.542 \):
\( 6099 \times 4.542 \approx 27700\space J \) (convert to kJ by dividing by 1000: \( 27.7\space kJ \))

Answer:

27.7 kJ (corresponding to the option "27.7 kJ")