Question

remember: you cant change the formulas!
reactants
h
o
products
h
o
__ h₂ + o₂ → __ h₂o
○ 4
○ 1
○ 2

Explanation:

Step1: Balance oxygen atoms

For the reaction \(H_2+O_2
ightarrow H_2O\), in \(O_2\) there are 2 oxygen atoms and in \(H_2O\) there is 1 oxygen atom. To balance oxygen, put a 2 in front of \(H_2O\). The equation becomes \(H_2 + O_2
ightarrow2H_2O\).

Step2: Balance hydrogen atoms

Now, in \(2H_2O\) there are 4 hydrogen atoms. In \(H_2\) there are 2 hydrogen atoms. So, put a 2 in front of \(H_2\). The balanced equation is \(2H_2+O_2 = 2H_2O\).

Answer:

The coefficients are \(2\) for \(H_2\), \(1\) for \(O_2\), and \(2\) for \(H_2O\). So the answer for the coefficient of \(H_2\) is \(2\), for \(O_2\) is \(1\), and for \(H_2O\) is \(2\).