QUESTION IMAGE
Question
*remember: isoelectronic means the same # of electrons, which also means identical electron configuration!
- **which ion is isoelectronic to mg⁺²?
a. ca⁺² b. cl⁻¹ c. na⁺¹ d. s⁻²
- **which pair has identical electron configurations?
a. s⁻² and cl⁻¹ c. k⁰ and na⁺¹
b. s⁰ and ar⁰ d. cl⁻¹ and k⁰
- *how do you know?
- *why might it be important to identify isoelectronic ions/atoms?
for each of the following atoms, write the full electron configuration.
- selenium atom 2. selenium ion with a charge of +4
- fluorine atom 4. fluoride ion with a charge of -1
- silver atom 6. silver ion with a charge of +1
1. Which ion is isoelectronic to \(Mg^{+2}\)?
- Step 1: Determine the number of electrons in \(Mg^{+2}\)
The atomic number of \(Mg\) is \(12\). For \(Mg^{+2}\), the number of electrons \(=12 - 2=10\)
- Step 2: Calculate the number of electrons for each option
- For \(Ca^{+2}\): Atomic number of \(Ca\) is \(20\). Number of electrons \(=20 - 2 = 18\)
- For \(Cl^{-1}\): Atomic number of \(Cl\) is \(17\). Number of electrons \(=17+1 = 18\)
- For \(Na^{+1}\): Atomic number of \(Na\) is \(11\). Number of electrons \(=11 - 1=10\)
- For \(S^{-2}\): Atomic number of \(S\) is \(16\). Number of electrons \(=16 + 2=18\)
2. Which pair has identical electron configurations?
- Step 1: Determine the electron - configuration for each species
- For \(S^{-2}\): Atomic number of \(S\) is \(16\). \(S^{-2}\) has \(16 + 2=18\) electrons. Electron - configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
- For \(Cl^{-1}\): Atomic number of \(Cl\) is \(17\). \(Cl^{-1}\) has \(17+1 = 18\) electrons. Electron - configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
- For \(K^{0}\): Atomic number of \(K\) is \(19\). Electron - configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}\)
- For \(Na^{+1}\): Atomic number of \(Na\) is \(11\). \(Na^{+1}\) has \(11 - 1 = 10\) electrons. Electron - configuration: \(1s^{2}2s^{2}2p^{6}\)
- For \(S^{0}\): Atomic number of \(S\) is \(16\). Electron - configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}\)
- For \(Ar^{0}\): Atomic number of \(Ar\) is \(18\). Electron - configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
3. How do you know?
- For isoelectronic species (question 1), we calculate the number of electrons for the given ion (\(Mg^{+2}\)) and for each of the options. Two species are isoelectronic if they have the same number of electrons.
- For identical electron - configurations (question 2), we write out the full electron - configuration (using the Aufbau principle: filling electrons in the order \(1s<2s<2p<3s<3p<4s<3d\) etc.) for each species in the pair. If the sequence of filled orbitals is the same, they have identical electron configurations
4. Why might it be important to identify isoelectronic ions/atoms?
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
s:
- Question 1: \(c. Na^{+1}\)
- Question 2: \(a. S^{-2}\) and \(Cl^{-1}\)