Question

reler to the accompanying data set and construct a 90% confidence interval estimate of the mean pulse rate of adult females, then do the same for adult males. compare the results.
click the icon to view the pulse rates for adult females and adult males.
construct a 90% confidence interval of the mean pulse rate for adult females.
72.10 bpm < μ < 79.30 bpm
(round to one decimal place as needed.)
construct a 90% confidence interval of the mean pulse rate for adult males
64.06 bpm < μ < 70.89 bpm
(round to one decimal place as needed.)
compare the results.
a. the confidence intervals overlap, so it appears that there is no difference in mean pulse rates between adult females and adult males
b. the confidence intervals do not overlap, so it appears that adult females have a higher mean pulse rate than adult males.
c. the confidence intervals do not overlap, so it appears that there is no difference in mean pulse rates between adult females and adult males
d. the confidence intervals overlap, so it appears that adult males have a higher mean pulse rate than adult females.

Explanation:

We are given the 90% confidence interval for adult females as \(72.1\ \text{bpm}<\mu < 79.3\ \text{bpm}\) and for adult males as \(64.1\ \text{bpm}<\mu < 70.9\ \text{bpm}\).

• For option A: The upper - limit of the male confidence interval (\(70.9\)) is less than the lower - limit of the female confidence interval (\(72.1\)). So, the intervals do not overlap.
• For option B: Since \(70.9<72.1\), the female confidence interval is entirely above the male confidence interval. So, adult females have a higher mean pulse rate.
• For option C: The non - overlapping of intervals implies a difference (not no difference).
• For option D: The intervals do not overlap and females have a higher mean (not males).

Answer:

B. The confidence intervals do not overlap, so it appears that adult females have a higher mean pulse rate than adult males.