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regular chemistry name: savannah jackson date: 10/10 class: 4th unit 2 …

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regular chemistry
name: savannah jackson date: 10/10 class: 4th
unit 2 - hw 3
ws 2: ionic bonding with transition metals and polyatomic ions
make sure you use the criss cross method correctly, and use the naming rules to name correctly.

  • metal names stay the same
  • nonmetals must get the suffix of -ide
  • transition metals (groups 3 - 12) must have roman numerals in their name
  • chromium (ii) → (ii) tells you that this chromium has a +2 charge
  • you can figure out the charge of the transition metal by completing the criss cross method backwards. the subscript on the nonmetal would become the charge for the transition metals
  • polyatomic ions are units, and should not be separated.
  • use your reference sheet to figure out the name or formula for the polyatomic ion.
  • if there are multiples of the polyatomic ion, put the polyatomic ion in parentheses

to complete the table below:

  • you will break into your lab groups.
  • at each station are 4 cards with names on them and numbers. those numbers correspond to the question name on the table below.
  • complete the compound using the cards at the stations. determine the formula and compound name for each.
metal or transition metalnonmetal or polyatomic ionformulacompound name
2. calciumcacncalcium chloride
3. copper (ii)
4. lead (iv)
5. nitride
6. borate
7. iodide
8. sulfite

Explanation:

Step1: Determine calcium's charge

Calcium is in Group 2, so it has a +2 charge ($Ca^{2 +}$). Chloride is $Cl^{-}$.

Step2: Apply criss - cross method

The 1 from $Cl^{-}$ goes to calcium and the 2 from $Ca^{2 +}$ goes to chlorine. The formula is $CaCl_{2}$.

Step3: Name the compound

Calcium is the metal (name stays the same) and chlorine is the non - metal which gets the suffix -ide. The name is calcium chloride.

Step4: Determine copper(II) charge

Copper(II) has a +2 charge ($Cu^{2+}$). Let's assume chloride ($Cl^{-}$) for now.

Step5: Apply criss - cross method for copper(II)

The 1 from $Cl^{-}$ goes to copper and the 2 from $Cu^{2 +}$ goes to chlorine. The formula is $CuCl_{2}$. The name is copper(II) chloride.

Step6: Determine lead(IV) charge

Lead(IV) has a +4 charge ($Pb^{4+}$). For chloride ($Cl^{-}$), applying criss - cross method, the 1 from $Cl^{-}$ goes to lead and the 4 from $Pb^{4 +}$ goes to chlorine. The formula is $PbCl_{4}$. The name is lead(IV) chloride.

Step7: For nitride ($N^{3-}$)

  • With sodium ($Na^{+}$), applying criss - cross method, the formula is $Na_{3}N$ and the name is sodium nitride.
  • With calcium ($Ca^{2+}$), the formula is $Ca_{3}N_{2}$ and the name is calcium nitride.
  • With copper(II) ($Cu^{2+}$), the formula is $Cu_{3}N_{2}$ and the name is copper(II) nitride.
  • With lead(IV) ($Pb^{4+}$), the formula is $Pb_{3}N_{4}$ and the name is lead(IV) nitride.

Step8: For borate ($BO_{3}^{3 -}$)

  • With sodium ($Na^{+}$), the formula is $Na_{3}BO_{3}$ and the name is sodium borate.
  • With calcium ($Ca^{2+}$), the formula is $Ca_{3}(BO_{3})_{2}$ and the name is calcium borate.
  • With copper(II) ($Cu^{2+}$), the formula is $Cu_{3}(BO_{3})_{2}$ and the name is copper(II) borate.
  • With lead(IV) ($Pb^{4+}$), the formula is $Pb_{3}(BO_{3})_{4}$ and the name is lead(IV) borate.

Step9: For iodide ($I^{-}$)

  • With sodium ($Na^{+}$), the formula is $NaI$ and the name is sodium iodide.
  • With calcium ($Ca^{2+}$), the formula is $CaI_{2}$ and the name is calcium iodide.
  • With copper(II) ($Cu^{2+}$), the formula is $CuI_{2}$ and the name is copper(II) iodide.
  • With lead(IV) ($Pb^{4+}$), the formula is $PbI_{4}$ and the name is lead(IV) iodide.

Step10: For sulfite ($SO_{3}^{2 -}$)

  • With sodium ($Na^{+}$), the formula is $Na_{2}SO_{3}$ and the name is sodium sulfite.
  • With calcium ($Ca^{2+}$), the formula is $CaSO_{3}$ and the name is calcium sulfite.
  • With copper(II) ($Cu^{2+}$), the formula is $CuSO_{3}$ and the name is copper(II) sulfite.
  • With lead(IV) ($Pb^{4+}$), the formula is $Pb(SO_{3})_{2}$ and the name is lead(IV) sulfite.

Answer:

Metal or Transition MetalNonmetal or Polyatomic ionFormulaCompound Name
CalciumChloride$CaCl_{2}$Calcium Chloride
Copper(II)Chloride$CuCl_{2}$Copper(II) Chloride
Lead(IV)Chloride$PbCl_{4}$Lead(IV) Chloride
SodiumNitride$Na_{3}N$Sodium Nitride
CalciumNitride$Ca_{3}N_{2}$Calcium Nitride
Copper(II)Nitride$Cu_{3}N_{2}$Copper(II) Nitride
Lead(IV)Nitride$Pb_{3}N_{4}$Lead(IV) Nitride
SodiumBorate$Na_{3}BO_{3}$Sodium Borate
CalciumBorate$Ca_{3}(BO_{3})_{2}$Calcium Borate
Copper(II)Borate$Cu_{3}(BO_{3})_{2}$Copper(II) Borate
Lead(IV)Borate$Pb_{3}(BO_{3})_{4}$Lead(IV) Borate
SodiumIodide$NaI$Sodium Iodide
CalciumIodide$CaI_{2}$Calcium Iodide
Copper(II)Iodide$CuI_{2}$Copper(II) Iodide
Lead(IV)Iodide$PbI_{4}$Lead(IV) Iodide
SodiumSulfite$Na_{2}SO_{3}$Sodium Sulfite
CalciumSulfite$CaSO_{3}$Calcium Sulfite
Copper(II)Sulfite$CuSO_{3}$Copper(II) Sulfite
Lead(IV)Sulfite$Pb(SO_{3})_{2}$Lead(IV) Sulfite