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refer to the following statement to answer parts (a) through (c) below.…

Question

refer to the following statement to answer parts (a) through (c) below. i dress quickly or take the express train, and i do not get to work on time.

a. write the statement in symbolic form. assign letters to simple statements that are not negated. choose the correct answer below.
a. let p = i dress quickly, let q = i take the express train, and let r = i get to work on time; (p ∨ q) ∧ ¬r
b. let p = i dress quickly, let q = i take the express train, and let r = i get to work on time; (p ∨ q) ∨ ¬r
c. let p = i dress quickly, let q = i take the express train, and let r = i do not get to work on time; (p ∧ q) ∨ ¬r
d. let p = i dress quickly, let q = i take the express train, and let r = i do not get to work on time; (p ∨ q) ∧ ¬r

b. construct a truth table for the symbolic statement in part (a).

pqrp ∨ q¬r(p ∨ q) ∧ ¬r

Explanation:

Part (a)

Step 1: Identify Simple Statements

Let \( p \) = "I dress quickly", \( q \) = "I take the express train", \( r \) = "I get to work on time". The negation of \( r \) (denoted \(
eg r \)) is "I do not get to work on time". The original statement is "I dress quickly or take the express train, and I do not get to work on time", which is \( (p \vee q) \wedge
eg r \). Now check the options:

  • Option A: \( p \) = "I dress quickly", \( q \) = "I take the express train", \( r \) = "I get to work on time", formula \( (p \vee q) \wedge

eg r \) – matches.

  • Option B: Formula is \( (p \vee q) \vee

eg r \) – incorrect (uses "or" instead of "and").

  • Option C: Formula is \( (p \wedge q) \vee

eg r \) – incorrect (uses "and" for \( p,q \) instead of "or").

  • Option D: Formula is \( (p \vee q) \wedge

eg r \) but \( r \) is "I do not get to work on time" (wrong, \( r \) should be "I get to work on time" for \(
eg r \) to be correct negation) – incorrect.

Step 2: Confirm the Correct Option

Only Option A has the correct simple statements and logical connectives.

Step 1: List All Truth Values for \( p, q, r \)

There are \( 2^3 = 8 \) combinations for \( p, q, r \) (each can be T or F):

\( p \)\( q \)\( r \)
TTF
TFT
TFF
FTT
FTF
FFT
FFF

Step 2: Compute \( p \vee q \)

\( p \vee q \) is T if \( p \) or \( q \) is T:

\( p \)\( q \)\( r \)\( p \vee q \)
TTFT
TFTT
TFFT
FTTT
FTFT
FFTF
FFFF

Step 3: Compute \(

eg r \)
\(
eg r \) is T when \( r \) is F, F when \( r \) is T:

\( p \)\( q \)\( r \)\( p \vee q \)\(

eg r \) |

TTTTF
TTFTT
TFTTF
TFFTT
FTTTF
FTFTT
FFTFF
FFFFT

Step 4: Compute \( (p \vee q) \wedge

eg r \)
This is T only when both \( p \vee q \) and \(
eg r \) are T:

\( p \)\( q \)\( r \)\( p \vee q \)\(

eg r \) | \( (p \vee q) \wedge
eg r \) |

TTTTFF
TTFTTT
TFTTFF
TFFTTT
FTTTFF
FTFTTT
FFTFFF
FFFFTF

Answer:

A. let \( p \) = I dress quickly, let \( q \) = I take the express train, and let \( r \) = I get to work on time; \( (p \vee q) \wedge
eg r \)

Part (b)