Question

reactions involving ionic salt solutions
naoh(aq) + cuso₄(aq)

Explanation:

Step1: Write the chemical reaction

$$2NaOH(aq)+CuSO_{4}(aq) ightarrow Cu(OH)_{2}(s)+Na_{2}SO_{4}(aq)$$

Step2: Analyze the reaction type

This is a double - displacement reaction. Copper hydroxide \(Cu(OH)_{2}\) is a blue precipitate. Sodium sulfate \(Na_{2}SO_{4}\) is soluble in water.

Step3: Determine the observations

Since \(Cu(OH)_{2}\) is formed as a solid, “Solid formed in mixture” is an observation.

Step4: Determine the products

From the balanced chemical equation, the products are \(Cu(OH)_{2}(s)\) and \(Na_{2}SO_{4}(aq)\)

Answer:

Observations after mixing: Solid formed in mixture
Products: \(Cu(OH)_{2}(s)\), \(Na_{2}SO_{4}(aq)\)