Question

reactions involving ionic salt solutions

naoh(aq) + cuso₄(aq)

nacl(aq) + pb(no₃)₂(aq)

bacl₂(aq) + h₂so₄(aq)

Explanation:

Step1: Write the chemical reaction equation

For \(NaOH(aq)+CuSO_{4}(aq)\):
The chemical reaction is \(2NaOH(aq)+CuSO_{4}(aq)=Cu(OH)_{2}(s)+Na_{2}SO_{4}(aq)\). A solid (\(Cu(OH)_{2}\)) is formed, so the observation “Solid formed in mixture” is correct. And the products are \(Cu(OH)_{2}(s)\) and \(Na_{2}SO_{4}(aq)\).
For \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\):
The chemical reaction is \(2NaCl(aq)+Pb(NO_{3})_{2}(aq)=PbCl_{2}(s)+2NaNO_{3}(aq)\). A solid (\(PbCl_{2}\)) is formed, so the observation “Solid formed in mixture” is correct. And the products are \(PbCl_{2}(s)\) and \(NaNO_{3}(aq)\).
For \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)\):
The chemical reaction is \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)=BaSO_{4}(s)+2HCl(aq)\). A solid (\(BaSO_{4}\)) is formed, so the observation “Solid formed in mixture” is correct. And the products are \(BaSO_{4}(s)\) and \(HCl(aq)\).

Answer:

For \(NaOH(aq)+CuSO_{4}(aq)\):

• Observations: Solid formed in mixture
• Products: \(Cu(OH)_{2}(s)\), \(Na_{2}SO_{4}(aq)\)

For \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\):

• Observations: Solid formed in mixture
• Products: \(PbCl_{2}(s)\), \(NaNO_{3}(aq)\)

For \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)\):

• Observations: Solid formed in mixture
• Products: \(BaSO_{4}(s)\), \(HCl(aq)\)