Question

a reaction occurs that results in a molecule with two atoms of the same element. the atoms share six electrons. which molecule could be the product of the reaction? (1 point)
n₂
o₂
si₂
f₂

Explanation:

• $F_2$: Each F atom has 7 valence electrons. In $F_2$, they share one pair (2 electrons) to form a single bond.
• $Si_2$: Si has 4 valence electrons. Sharing 6 electrons would not follow common bonding patterns for Si.
• $O_2$: Each O atom has 6 valence electrons. They share 2 pairs (4 electrons) to form a double bond.
• $N_2$: Each N atom has 5 valence electrons. They share 3 pairs (6 electrons) to form a triple bond, which satisfies the condition of sharing six electrons.

Answer:

$N_2$