Question

a reaction of 12.640 g of copper oxide with 0.316 g hydrogen produces 2.844 g of water and x g of copper. x = ____ g

Explanation:

Step1: Apply the law of conservation of mass

The law of conservation of mass states that the mass of reactants is equal to the mass of products.
The mass of reactants is the sum of the mass of copper oxide ($m_{CuO}=12.640\ g$) and the mass of hydrogen ($m_{H_2}=0.316\ g$), so $m_{reactants}=m_{CuO}+m_{H_2}$.
The mass of products is the sum of the mass of water ($m_{H_2O} = 2.844\ g$) and the mass of copper ($m_{Cu}=X$), so $m_{products}=m_{H_2O}+m_{Cu}$.
According to the law of conservation of mass: $m_{CuO}+m_{H_2}=m_{H_2O}+m_{Cu}$.

Step2: Solve for \(X\)

Rearrange the equation from Step 1 to solve for \(X\):

$$
LATEXBLOCK0
$$

Answer:

$10.112$