Question

the ratio of h₂ gas to o₂ gas will always remain 2:1, and the ratio of h₂ gas to h₂o gas will remain 1:1 so if the gas volumes are measured at the same temperature and pressure: 44.8 liters of h₂ + liters of o₂ → liters of h₂o

Explanation:

Step1: Calculate the volume of \(O_2\)

Given the ratio of \(H_2\) to \(O_2\) is \(2:1\). Let the volume of \(O_2\) be \(x\) liters.
We have the proportion \(\frac{V_{H_2}}{V_{O_2}}=\frac{2}{1}\). Substituting \(V_{H_2} = 44.8\) liters, we get \(\frac{44.8}{x}=\frac{2}{1}\).
Cross - multiplying gives \(2x=44.8\), so \(x = 22.4\) liters.

Step2: Calculate the volume of \(H_2O\)

Given the ratio of \(H_2\) to \(H_2O\) is \(1:1\). Let the volume of \(H_2O\) be \(y\) liters.
We have the proportion \(\frac{V_{H_2}}{V_{H_2O}}=\frac{1}{1}\). Substituting \(V_{H_2}=44.8\) liters, we get \(y = 44.8\) liters.

Answer:

44.8 liters of \(H_2+22.4\) liters of \(O_2
ightarrow44.8\) liters of \(H_2O\)