Question

rank the following from least electronegative to most:

1. ba
2. v
3. si
4. o

Explanation:

Step1: Recall the trend of electronegativity

Electronegativity increases across a period from left to right and decreases down a group in the periodic table.

Step2: Analyze the positions of the elements

• Ba (Barium) is in Group 2, Period 6.
• V (Vanadium) is in Group 5, Period 4.
• Si (Silicon) is in Group 14, Period 3.
• O (Oxygen) is in Group 16, Period 2.

Step3: Compare electronegativity values

Based on the trend: Ba < V < Si < O

Answer:

Ba, V, Si, O