Question

quiz #2:chapter 4
0:29:50 remaining
page 1 of 5
you can use this periodic table during the quiz.
however, as stated in the course outline, and in
the orientation session, this quiz is not open book.
you cannot access course material while you write
the quiz. nor can you google your answers, work as
a group, use a cheat sheet, etc.
question 1 (1 point)
vsepr predicts an sbf₅ molecule will be which of
the following shapes?
tetrahedral
trigonal bipyramidal
square pyramid
trigonal planar
square planar

Explanation:

Step1: Determine the central atom

The central atom in \(SbF_5\) is \(Sb\).

Step2: Calculate the valence - electron number of the central atom

The valence - electron number of \(Sb\) is \(5\).

Step3: Calculate the electron - pair number around the central atom

Since \(Sb\) forms \(5\) single bonds with \(F\) atoms (no lone pairs on \(Sb\) as \(5\) valence electrons are used in bonding), the electron - pair number is \(5\).

Step4: Apply VSEPR theory

According to VSEPR theory, when the electron - pair number is \(5\), the molecular shape is trigonal bipyramidal.

Answer:

trigonal bipyramidal