quiz : balancing chemical reactions
balance the following reaction (enter the coefficients)
cl₂ + nabr → nacl + br₂

Question

Accepted Answer

# Explanation:
## Step1: Balance the chlorine atoms
On the left - hand side, we have $Cl_2$ (2 chlorine atoms). On the right - hand side, we have $NaCl$. Let the coefficient of $Cl_2$ be $a$, the coefficient of $NaBr$ be $b$, the coefficient of $NaCl$ be $c$, and the coefficient of $Br_2$ be $d$. For chlorine: $2a=c$.
## Step2: Balance the bromine atoms
On the left - hand side, we have $b$ bromine atoms (from $NaBr$), and on the right - hand side, we have $2d$ bromine atoms (from $Br_2$). So $b = 2d$.
## Step3: Balance the sodium atoms
On the left - hand side, we have $b$ sodium atoms (from $NaBr$), and on the right - hand side, we have $c$ sodium atoms (from $NaCl$). So $b=c$.
Let $a = 1$. Then $c=2$ (from chlorine balance). Since $b = c$, $b = 2$. And since $b = 2d$, $d = 1$.

# Answer:
$1$ $Cl_2+2$ $NaBr
ightarrow2$ $NaCl + 1$ $Br_2$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the chlorine atoms

Step2: Balance the bromine atoms

Step3: Balance the sodium atoms

Answer: