Question

question 6
which of the following is correct about the balanced equation shown?
c₂h₅oh (l) + 3 o₂ (g) → 2 co₂ (g) + 3 h₂o (g)
a oxygen gas is always in excess for this reaction.
b two moles of water a produced.
c ethanol is a reactant.
d oxygen gas is a product.

Explanation:

Step1: Analyze the reaction equation

In the reaction \(C_2H_5OH(l)+3O_2(g)\to2CO_2(g)+3H_2O(g)\), reactants are on the left - hand side of the arrow (\(C_2H_5OH\) and \(O_2\)), and products are on the right - hand side (\(CO_2\) and \(H_2O\)).

Step2: Check each option

• Option A:

Oxygen gas (\(O_2\)) is a reactant, not always in excess. The stoichiometry of the reaction is based on the balanced equation as it is, and there is no information given in the problem to suggest \(O_2\) is in excess.

• Option B:

From the balanced equation \(C_2H_5OH(l)+3O_2(g)\to2CO_2(g)+3H_2O(g)\), the coefficient of \(H_2O\) is 3, so 3 moles of water are produced, not 2 moles.

• Option C:

In the reaction \(C_2H_5OH(l)+3O_2(g)\to2CO_2(g)+3H_2O(g)\), \(C_2H_5OH\) (ethanol) is on the left - hand side of the arrow. In a chemical reaction, substances on the left - hand side of the arrow are reactants.

• Option D:

Oxygen gas (\(O_2\)) is a reactant (on the left - hand side of the arrow), not a product.

Answer:

C. Ethanol is a reactant.