Question

question
what is the poh of a solution at 25.0°c with h₃o⁺ = 9.90 × 10⁻¹² m?

• report your answer to three decimal places (four significant figures).

provide your answer below:
poh =

Explanation:

Step1: Calculate pH

The formula for pH is \(pH = -\log[H_3O^+]\).
Given \([H_3O^+]=9.90\times 10^{-12}\space M\), then \(pH=-\log(9.90\times 10^{-12})\).
Using the logarithm property \(\log(ab)=\log a+\log b\), we have \(pH = -(\log9.90+\log(10^{-12}))\).
Since \(\log(10^{-12})=- 12\) and \(\log9.90\approx0.996\), \(pH=- (0.996 - 12)=11.004\).

Step2: Calculate pOH

At \(25.0^{\circ}C\), the relationship between pH and pOH is \(pH + pOH=14\).
So, \(pOH = 14 - pH\).
Substitute \(pH = 11.004\) into the formula, \(pOH=14 - 11.004 = 2.996\).

Answer:

\(2.996\)