Question

question 4
what is the mole ratio of oxygen to sodium acetate in nac₂h₃o₂?
1 mol o : 2 mol nac₂h₃o₂
1 mol o : 1 mol nac₂h₃o₂
2 mol o : 1 mol nac₂h₃o₂
2 mol o : 2 mol nac₂h₃o₂

Explanation:

Step1: Analyze the formula of sodium acetate

The formula of sodium acetate is \(NaC_{2}H_{3}O_{2}\). In one molecule of \(NaC_{2}H_{3}O_{2}\), there are 2 oxygen atoms.

Step2: Determine the mole ratio

If we consider 1 mole of \(NaC_{2}H_{3}O_{2}\), since there are 2 oxygen atoms in one molecule of \(NaC_{2}H_{3}O_{2}\), the number of moles of oxygen is 2 moles for 1 mole of \(NaC_{2}H_{3}O_{2}\). So the mole ratio of oxygen to sodium acetate is \(2\space mol\space O:1\space mol\space NaC_{2}H_{3}O_{2}\)

Answer:

\(2\space mol\space O:1\space mol\space NaC_{2}H_{3}O_{2}\) (the third option)