Question

question 1. what is the correct formula for the ionic compound formed between the copper(ii) ion and the oxide ion?
○ cuo
○ cuo₂
○ cu₂o
○ cu₂o₂

Explanation:

Step1: Identify Ions' Charges

Copper(II) ion is $\text{Cu}^{2+}$, oxide ion is $\text{O}^{2-}$.

Step2: Balance Charges

To form a neutral compound, the total positive charge equals total negative charge. For $\text{Cu}^{2+}$ and $\text{O}^{2-}$, the ratio of $\text{Cu}^{2+}$ to $\text{O}^{2-}$ is 1:1 (since $2+ + 2- = 0$). So the formula is $\text{CuO}$.

Answer:

A. $\text{CuO}$ (assuming the first option is labeled A, as the options are $\text{CuO}$, $\text{CuO}_2$, $\text{Cu}_2\text{O}$, $\text{Cu}_2\text{O}_2$)