Question

question 5 of 9
step 1: how many moles of naoh are present in 14.5 ml of 0.250 m naoh?
moles of naoh: mol

Explanation:

Step1: Convert volume to liters

The formula for molarity \(M=\frac{n}{V}\) (where \(n\) is moles and \(V\) is volume in liters). Given \(V = 14.5\space mL\). Convert to liters: \(V=14.5\times10^{- 3}\space L\) (since \(1\space L = 1000\space mL\)).

Step2: Rearrange the molarity formula to solve for moles

From \(M=\frac{n}{V}\), we can solve for \(n\) (moles). So \(n = M\times V\). Given \(M = 0.250\space M\) and \(V=14.5\times 10^{-3}\space L\). Then \(n=(0.250\space mol/L)\times(14.5\times 10^{-3}\space L)\)

$$n = 0.250\times14.5\times10^{-3}\space mol$$

$$n=3.625\times10^{-3}\space mol$$

Answer:

\(3.625\times 10^{-3}\)