Question

question 3
1 pts
calculate the percent composition of hydrogen in ammonium sulfide.
10.1%
25.3%
17.9%
11.8%

Explanation:

Step1: Determine the formula of ammonium sulfide

Ammonium sulfide has the formula \((NH_4)_2S\).

Step2: Calculate the molar mass of \((NH_4)_2S\)

• Molar mass of \(N\): \(14.01\space g/mol\), there are \(2\) \(N\) atoms (\(2\times14.01 = 28.02\space g/mol\))
• Molar mass of \(H\): \(1.008\space g/mol\), there are \(8\) \(H\) atoms (\(8\times1.008=8.064\space g/mol\))
• Molar mass of \(S\): \(32.07\space g/mol\), there is \(1\) \(S\) atom (\(32.07\space g/mol\))
• Molar mass of \((NH_4)_2S\): \(28.02 + 8.064+32.07=68.154\space g/mol\)

Step3: Calculate the percent composition of \(H\)

Percent composition of \(H=\frac{\text{Mass of }H}{\text{Molar mass of }(NH_4)_2S}\times100\%=\frac{8.064}{68.154}\times 100\%\approx11.8\%\)

Answer:

\(11.8\%\) (the fourth option)