Question

question 1 (2 points)
what is the temperature of 2.00 moles of oxygen in 5.00 l at 2.00 atm?
this a 1 type of problem so we use the equation 2.
rearrange the equation for 3, input the variables, then solve mathematically.
a. missing variable b. change in conditions c. density d. molar volume at stp
e. partial pressure f. 1 mol = 22.4 l g. d = m/v h. pv = nrt
i. p2v2/n2t2 = p1v1/n1t1 j. ptotal = p1 + p2 + …… k. p l. p1 m. p2
n. v o. v1 p. v2 q. n r. n1 s. n2 t. r u. t
v. t1 w. t2 x. 1.25 y. 12.5 z. 125

Explanation:

1. Since we are given values for pressure (\(P = 2.00\) atm), volume (\(V=5.00\) L), and moles (\(n = 2.00\) mol) and we need to find the temperature (\(T\)), it is a missing - variable problem.
2. The ideal gas law \(PV=nRT\) is the appropriate equation for relating pressure, volume, moles, and temperature of a gas.
3. We need to rearrange the ideal gas law \(PV = nRT\) for \(T\). Starting with \(PV=nRT\), we can solve for \(T\) by dividing both sides of the equation by \(nR\), so \(T=\frac{PV}{nR}\). The gas constant \(R = 0.0821\space L\cdot atm/(mol\cdot K)\).

Answer:

1. A. missing variable
2. H. \(PV = nRT\)
3. U. \(T\)