Question

question 1 (2 points)
the correct lewis dot structure for boron would have:
the symbol bo with 3 single dots.
the symbol b with 2 single dots.
the symbol b with 3 single dots.
the symbol b with 4 paired dots.

Explanation:

Lewis Dot structures use the element's symbol and dots to represent valence electrons. Boron (B) has an atomic number of 5. Its electron configuration is \(1s^{2}2s^{2}2p^{1}\). The valence electrons (in the \(n = 2\) shell) are \(2s^{2}2p^{1}\), so there are 3 valence electrons. The symbol for boron is B (not Bo). Each dot represents a valence electron. So, it should be the symbol B with 3 single dots.

Answer:

the symbol B with 3 single dots.