Question

question 5 (1 point)
a stock solution is used to make a dilute solution for an experiment. the stock solution is
3.50 m. you need to make 100. ml of a 0.630 m solution. what volume of stock is needed
to make the dilute solution?
18.0 l
0.0180 l
0.556 l
0.018 l

Explanation:

Step1: Use the dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\), where \(C_1\) is the concentration of the stock solution, \(V_1\) is the volume of the stock solution, \(C_2\) is the concentration of the dilute solution, and \(V_2\) is the volume of the dilute solution.
Given \(C_1 = 3.50\space M\), \(C_2=0.630\space M\), \(V_2 = 100\space mL=0.1\space L\).
We need to find \(V_1\).
From \(C_1V_1 = C_2V_2\), we can solve for \(V_1\) as \(V_1=\frac{C_2V_2}{C_1}\).

Step2: Substitute the values into the formula

Substitute \(C_1 = 3.50\space M\), \(C_2 = 0.630\space M\), and \(V_2=0.1\space L\) into \(V_1=\frac{C_2V_2}{C_1}\).
\(V_1=\frac{0.630\space M\times0.1\space L}{3.50\space M}\)
\(V_1=\frac{0.063}{3.50}\space L\)
\(V_1 = 0.018\space L\)

Answer:

\(0.018\space L\)