Question

question 8 (1 point)
given the following reaction mechanism, what is the equation for the overall reaction?
2a --> b + 2c (slow)
b + c --> d + e (fast)
c + d --> e + f (fast)
2a --> 2e + f
2a + b + 2c --> d + 2e + f
2a + 2c --> 2e + f
2a + b + 2c + d --> b + 2c + d + 2e + f
2a + c --> 2e + f

Explanation:

Step1: Add all the equations

$$\begin{align*} 2A&\to B + 2C\\ B + C&\to D + E\\ C + D&\to E + F\\ \end{align*}$$

Adding them together: \(2A+(B + C)+(C + D)\to(B + 2C)+(D + E)+(E + F)\)

Step2: Cancel out common terms

Cancel \(B\), \(C\), and \(D\) on both sides.
Left - hand side: \(2A + C\)
Right - hand side: \(2E+F\)

Answer:

\(2A + C\to2E + F\) (the fifth option)