Question

question 6 (1 point)
consider the following structure of a compound:

the compound is an isomer of
a) propene
b) propyne
c) propane
d) cyclopropene
e) cyclopentene

Explanation:

Step1: Determine the molecular formula of the given compound

The given compound is cyclopropane. The general formula for cycloalkanes is \(C_nH_{2n}\). For cyclopropane (\(n = 3\)), the molecular formula is \(C_3H_6\).

Step2: Determine the molecular formula of each option

• a) Propene: The formula for alkenes is \(C_nH_{2n}\). For propene (\(n=3\)), the formula is \(C_3H_6\).
• b) Propyne: The formula for alkynes is \(C_nH_{2n - 2}\). For propyne (\(n = 3\)), the formula is \(C_3H_4\).
• c) Propane: The formula for alkanes is \(C_nH_{2n+ 2}\). For propane (\(n=3\)), the formula is \(C_3H_8\).
• d) Cyclopropene: Cyclopropene has a double bond in the ring. Its formula is \(C_3H_4\) (since it has one ring and one double - bond, degree of unsaturation \(=2\), and using \(C_nH_{2n-2}\) for \(n = 3\)).
• e) Cyclopentene: For cyclopentene (\(n = 5\)), using \(C_nH_{2n-2}\) (one ring and one double - bond), the formula is \(C_5H_8\).

Step3: Check for isomerism

Isomers have the same molecular formula but different structures. Since the given compound (\(C_3H_6\)) and propene (\(C_3H_6\)) have the same molecular formula but different structures (one is a cycloalkane and the other is an alkene), they are isomers.

Answer:

A. propene