Question

question 1
a little more difficult problem.
what is the molarity of 2.50 l of solution containing 5.25 grams of sulfuric acid?
(hint: you have to turn the grams of the solute to moles of the solute.)
○ 0.0134 m
○ 0.0214 m
○ 0.677 m
○ 2.10 m

Explanation:

Step1: Find molar mass of \(H_2SO_4\)

Molar mass of \(H = 1.008\ g/mol\), \(S = 32.07\ g/mol\), \(O = 16.00\ g/mol\).
Molar mass of \(H_2SO_4 = 2(1.008) + 32.07 + 4(16.00) = 98.09\ g/mol\).

Step2: Calculate moles of \(H_2SO_4\)

Moles \(= \frac{\text{mass}}{\text{molar mass}} = \frac{5.25\ g}{98.09\ g/mol} \approx 0.0535\ mol\).

Step3: Calculate molarity (\(M\))

Molarity \(= \frac{\text{moles of solute}}{\text{volume of solution (L)}} = \frac{0.0535\ mol}{2.50\ L} \approx 0.0214\ M\).

Answer:

0.0214 M (corresponding to the option "0.0214 M")