Question

question 2
fill in the coefficients to balance the following equation. include 1 as opposed to leaving any of the spaces blank.
nh₃ + cuo → n₂ + cu + h₂o

Explanation:

Step1: Balance nitrogen atoms

On the left side, nitrogen is in \(NH_3\), and on the right side, it is in \(N_2\). To balance nitrogen, if we put a coefficient of \(2\) in front of \(NH_3\), we have \(2\) nitrogen atoms on the left. So far, the equation is \(2NH_3+\square CuO
ightarrow1N_2+\square Cu+\square H_2O\)

Step2: Balance hydrogen atoms

Since we have \(2NH_3\), there are \(2\times3 = 6\) hydrogen atoms on the left. In \(H_2O\), if we put a coefficient of \(3\) in front of \(H_2O\), we have \(3\times2=6\) hydrogen atoms. Now the equation is \(2NH_3+\square CuO
ightarrow1N_2+\square Cu + 3H_2O\)

Step3: Balance oxygen atoms

In \(3H_2O\), there are \(3\) oxygen atoms. Since oxygen comes from \(CuO\), if we put a coefficient of \(3\) in front of \(CuO\), we have \(3\) oxygen atoms on the left. The equation becomes \(2NH_3 + 3CuO
ightarrow1N_2+\square Cu+3H_2O\)

Step4: Balance copper atoms

In \(3CuO\), there are \(3\) copper atoms. So we put a coefficient of \(3\) in front of \(Cu\). The balanced equation is \(2NH_3+3CuO = 1N_2+3Cu + 3H_2O\)

Answer:

Part 1: \(2\)
Part 2: \(3\)
Part 3: \(1\)
Part 4: \(3\)
Part 5: \(3\)