Question

question 2. the diagram below illustrates the formation of an ionic bond between a metal and a nonmetal. use the drag-and-drop options provided to: 1. label the charges of the ions formed (positive or negative). 2. drag and drop the correct chemical formula of the ionic compound into the designated area. al + :o: :o: al al :o: :o: :o: chemical formula 2⁺ 1⁺ 3⁺ 2⁻ 1⁻ 3⁻ al₃o₂ alo al₂o₃ al₂o₂ al₃o₃

Explanation:

Step1: Determine Ion Charges

Aluminum (Al) is a metal in group 13, so it loses 3 electrons, forming \( \text{Al}^{3+} \). Oxygen (O) is a nonmetal in group 16, gaining 2 electrons to form \( \text{O}^{2-} \).

Step2: Balance Charges for Formula

To balance charges in the ionic compound, use the crisscross method. The charge of Al (\( 3^+ \)) becomes the subscript of O, and the charge of O (\( 2^- \)) becomes the subscript of Al. So, \( \text{Al}_2\text{O}_3 \) (since \( 2 \times 3^+ + 3 \times 2^- = 0 \), balancing charges).

Answer:

For ion charges: Al ions get \( 3^+ \), O ions get \( 2^- \). For the chemical formula: \( \text{Al}_2\text{O}_3 \)