Question

question
for a certain class, the following data table compares how many students have a brother or a sister. what is the probability that a randomly chosen student from the class does not have a sister?
(table:

	has a sister	does not have a sister
does not have a brother	4	11

)
answer attempt 1 out of 2

Explanation:

Step1: Find total students without a sister

To find the number of students who do not have a sister, we add the number of students who do not have a sister and have a brother, and those who do not have a sister and do not have a brother. From the table, that's \(12 + 11 = 23\).

Step2: Find total number of students

First, find the number of students who have a sister: \(3 + 4 = 7\). Then, total students are those with a sister plus those without a sister: \(7 + 23 = 30\).

Step3: Calculate the probability

The probability that a randomly chosen student does not have a sister is the number of students without a sister divided by the total number of students. So, \(\frac{23}{30}\).

Answer:

\(\frac{23}{30}\)