Question

question 54 (4 points) give the formula for titanium (iv) cyanide. click/scroll on the u button to get superscripts and subscripts. paragraph b i u a

Explanation:

Step1: Determine ion charges

Titanium (IV) has a charge of $Ti^{4 + }$, and the cyanide ion is $CN^-$.

Step2: Balance charges

To balance the +4 charge of titanium, we need 4 cyanide ions.

Answer:

$Ti(CN)_4$