Question

question 23 (2 points)
write a complete electron configuration for an ion with 3+ charge in period 6, group 13

Explanation:

Step1: Identify the neutral atom

Period 6, Group 13 → Thallium (Tl), atomic number 81. Neutral Tl: 81 electrons.

Step2: Calculate ion electrons

3+ charge → lose 3 electrons: 81-3=78 electrons.

Step3: Write electron configuration

Fill orbitals by Aufbau principle up to 78 electrons: $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}$

Answer:

$1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}$