Question

question 20 of 20
construct the expression for ksp for solid ba₃(po₄)₂ in aqueous solution.
ba₃(po₄)₂(s) ⇌ 3 ba²⁺(aq) + 2 po₄³⁻(aq)
based on your knowledge of how the solid will dissociate in aqueous solution, construct the expression for the solubility constant, ksp. each reaction participant must be represented by one tile.
ksp =

Explanation:

Step1: Recall the formula for \(K_{sp}\)

For a general dissolution reaction \(A_xB_y(s)
ightleftharpoons xA^{m +}(aq)+yB^{n -}(aq)\), the solubility - product constant is given by \(K_{sp}=[A^{m +}]^x[B^{n -}]^y\). Solids (\(A_xB_y(s)\)) do not appear in the \(K_{sp}\) expression.

Step2: Identify \(x\), \(y\), \(A^{m +}\), and \(B^{n -}\) for \(Ba_3(PO_4)_2\)

In the reaction \(Ba_3(PO_4)_2(s)
ightleftharpoons3Ba^{2 +}(aq)+2PO_4^{3 -}(aq)\), we have \(A = Ba^{2+}\), \(x = 3\), \(B=PO_4^{3 -}\), and \(y = 2\).

Step3: Write the \(K_{sp}\) expression

Substitute into the \(K_{sp}\) formula: \(K_{sp}=[Ba^{2 +}]^3[PO_4^{3 -}]^2\). Since there are no reactants in the aqueous or gaseous phase (the reactant is a solid), the denominator is \(1\).

Answer:

\(K_{sp}=[Ba^{2+}]^3[PO_4^{3 -}]^2\)