Question

question 18 (1 point)
what will happen to the volume of a gas if its absolute temperature triples (increases by a factor of three) as the amount of gas and the pressure is held constant?
the volume will double (increase by a factor of two).
the volume will be cut in half (decrease by a factor of two).
the volume will triple (increase by a factor of three).
the volume will decrease by a factor of three.

Explanation:

Step1: Recall Charles's Law

Charles's Law is \(V = kT\) (where \(V\) is volume, \(T\) is absolute temperature, and \(k\) is a constant when pressure \(P\) and amount of gas \(n\) are constant).

Step2: Analyze the change

If \(T_{new}=3T_{old}\), then \(V_{new}=k\times T_{new}\). Substitute \(T_{new}\): \(V_{new}=k\times3T_{old}\). Since \(V_{old} = kT_{old}\), we have \(V_{new}=3V_{old}\). So the volume triples.

Answer:

C. The volume will triple (increase by a factor of three).