Question

question 15 (1 point)
quantities of water and 8.00 mol/l potassium nitrate solution are mixed to produce 700 ml solution with a final concentration of 6.00 mol/l. what volumes of water and potassium nitrate solution are used?
647.5 ml of 8.00 mol/l potassium nitrate and 52.5 ml of water
68.6 ml of 8.00 mol/l potassium nitrate and 631.4 ml of water
525 ml of 8.00 mol/l potassium nitrate and 175 ml ml of water
equal quantities of both

Explanation:

Step1: Use the dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\). Here, \(C_1 = 8.00\space mol/L\), \(C_2=6.00\space mol/L\), and \(V_2 = 700\space mL\). We need to find \(V_1\) (volume of \(8.00\space mol/L\) \(KNO_3\) solution).

$$V_1=\frac{C_2V_2}{C_1}$$

Step2: Calculate \(V_1\)

Substitute the values into the formula:

$$V_1=\frac{6.00\space mol/L\times700\space mL}{8.00\space mol/L}= 525\space mL$$

Step3: Calculate the volume of water

The total volume of the final solution \(V_2 = V_1+V_{water}\). So, \(V_{water}=V_2 - V_1\)

$$V_{water}=700\space mL - 525\space mL=175\space mL$$

Answer:

525 mL of 8.00 mol/L potassium nitrate and 175 mL of water.