Question

question 13
1 pts
how many moles in 510.0 g of al₂s₃?
4.318 mol
5.604 mol
8.637 mol
3.396 mol
question 14
1 pts
how many moles of sulfur are in 510.0 g of al₂s₃?
3.396 mol
6.792 mol
10.19 mol
1.132 mol

Explanation:

Step1: Calculate molar mass of Al₂S₃

The molar mass of Al is 26.98 g/mol and of S is 32.07 g/mol. For Al₂S₃, molar mass $M=(2\times26.98 + 3\times32.07)$ g/mol$=(53.96+96.21)$ g/mol = 150.17 g/mol.

Step2: Calculate moles of Al₂S₃ in 510.0 g

Use the formula $n=\frac{m}{M}$, where $m = 510.0$ g and $M = 150.17$ g/mol. So $n=\frac{510.0}{150.17}\approx3.396$ mol.

Step3: Calculate moles of sulfur in 510.0 g of Al₂S₃

In one - mole of Al₂S₃, there are 3 moles of S. Since there are 3.396 mol of Al₂S₃, the moles of S is $3\times3.396 = 10.188\approx10.19$ mol.

Answer:

Question 13: 3.396 mol
Question 14: 10.19 mol