Question

question 10
the number of moles of mgo produced when 0.20 mole of o₂ reacts completely is
2mg + o₂ → 2mgo
0.40 mol
0.20 mol
0.10 mol
0.60 mol
0.80 mol

Explanation:

Step1: Analyze the mole ratio

From the balanced chemical equation \(2Mg + O_{2}\to2MgO\), the mole ratio of \(O_{2}\) to \(MgO\) is \(1:2\).

Step2: Calculate the moles of \(MgO\)

If \(n(O_{2}) = 0.20\space mol\), using the mole ratio \(\frac{n(MgO)}{n(O_{2})}=\frac{2}{1}\), then \(n(MgO)=2\times n(O_{2})\). Substitute \(n(O_{2}) = 0.20\space mol\) into the equation: \(n(MgO)=2\times0.20\space mol\)

Answer:

\(0.40\space mol\) (the first option)