Question

question 10 of 25
suppose a normal distribution has a mean of 89 and a standard deviation of

1. what is ( p(xleq82) )?

a. 0.025
b. 0.84
c. 0.16
d. 0.975

Explanation:

Step1: Calculate z-score

$z = \frac{x - \mu}{\sigma} = \frac{82 - 89}{7} = -1$

Step2: Find probability for z=-1

Using standard normal table, $P(Z \leq -1) \approx 0.16$

Answer:

C. 0.16