Question

provide the product according to the request, markovnikov or anti - markovnikov.

a.

b.

c.

d.

Explanation:

rxn I

Markovnikov's rule states that in the addition of \( H - X \) to an alkene, the hydrogen atom adds to the carbon atom with more hydrogen atoms (or less substituted carbon in terms of alkyl groups). For the given cycloalkene in rxn I, the more substituted carbon (the one attached to the methyl group) will get the \( -OH \) (since \( H \) adds first according to Markovnikov, and then \( -OH \) in the hydration - like process). So the \( -OH \) is on the more substituted carbon.

rxn II

Anti - Markovnikov addition of \( H - Br \) (in the presence of peroxide, for example) means that the bromine atom adds to the less substituted carbon. For the given alkene in rxn II, the less substituted carbon (the terminal carbon of the double - bond, the one with more \( H \) atoms initially) will get the \( -Br \) atom.

Answer:

A.