Question

a professor records the following final grades in one course. construct a frequency table for the grades.
a a a b b b b b b b b c
c c c c c c d d d d d f

complete the table.
(type an integer or decimal rounded to the nearest tenth as needed.)
grade frequency relative frequency cumulative frequency
a 3 12.5 % 3
b 8 33.3 % 11
c 7 29.2 % 18
d □ □% □

Explanation:

Step1: Find Frequency of D

Count the number of Ds in the grade list. The grades are: A,A,A,B,B,B,B,B,B,B,C,C,C,C,C,C,D,D,D,D,D,F. Wait, earlier count for B: let's recount all grades. A:3, B: let's see, first row after A: B,B,B,B,B,B,B,B (8), then C: first row C, then second row C,C,C,C,C,C (total 7), D: second row D,D,D,D,D (5), F:1. Wait, original problem's grade list: first row: A A A B B B B B B B C (wait, maybe a typo, but the given frequency for A is 3, B is 8, C is 7. Let's sum existing frequencies: 3 (A) +8 (B)+7 (C) =18. Then D and F: total grades should be 3+8+7+5+1=24? Wait, but let's check the Ds: in the second row, D,D,D,D,D: that's 5. So frequency of D is 5.

Step2: Calculate Relative Frequency of D

Relative frequency = (Frequency of D / Total number of grades) 100. Total number of grades: 3 (A) +8 (B)+7 (C)+5 (D)+1 (F) =24. So relative frequency for D: (5/24)100 ≈20.8% (rounded to nearest tenth).

Step3: Calculate Cumulative Frequency of D

Cumulative frequency is sum of frequencies up to D. So cumulative frequency for D = cumulative frequency of C (18) + frequency of D (5) =23.

Answer:

For Grade D:
Frequency: 5
Relative frequency: 20.8%
Cumulative frequency: 23

(So filling the table:
D | 5 | 20.8% | 23)