Question

the pressure that a gas exerts on a sealed container changes from 3.74 atm to a new pressure when the temperature changes from 394 k to 789 k. what is the new pressure? p = ? atm

Explanation:

Step1: Apply Gay-Lussac's Law

$\frac{P_1}{T_1} = \frac{P_2}{T_2}$
$P_2 = P_1 \times \frac{T_2}{T_1}$

Step2: Substitute values

$P_2 = 3.74\ \text{atm} \times \frac{789\ \text{K}}{394\ \text{K}}$

Step3: Calculate new pressure

$P_2 \approx 3.74 \times 2.0025 \approx 7.49\ \text{atm}$

Answer:

7.49 atm