Question

predict the products of the reaction below. that is, complete the

hno_{3}+ba(oh)_{2}→

Explanation:

Step1: Identify the reaction type

This is an acid - base neutralization reaction. In an acid - base reaction, an acid ($\ce{HNO3}$) reacts with a base ($\ce{Ba(OH)2}$) to form a salt and water.

Step2: Write the general form of the reaction

The general form of an acid - base reaction is $\ce{acid+base -> salt + water}$. For $\ce{HNO3}$ (nitric acid) and $\ce{Ba(OH)2}$ (barium hydroxide), the hydrogen ($\ce{H+}$) from the acid combines with the hydroxide ($\ce{OH-}$) from the base to form water ($\ce{H2O}$), and the remaining ions form the salt.

Step3: Balance the chemical equation

The chemical equation is $\ce{2HNO3 + Ba(OH)2->Ba(NO3)2 + 2H2O}$.

• For hydrogen ($\ce{H}$): On the left - hand side, in $\ce{2HNO3}$ there are $2$ $\ce{H}$ atoms from $\ce{HNO3}$ and $2$ $\ce{H}$ atoms from $\ce{Ba(OH)2}$ (since $\ce{Ba(OH)2}$ has $2$ $\ce{OH-}$ groups). On the right - hand side, in $\ce{2H2O}$ there are $2\times2 = 4$ $\ce{H}$ atoms.
• For nitrate ($\ce{NO3-}$): In $\ce{2HNO3}$ there are $2$ $\ce{NO3-}$ groups, and in $\ce{Ba(NO3)2}$ there are $2$ $\ce{NO3-}$ groups.
• For barium ($\ce{Ba}$): There is $1$ $\ce{Ba}$ atom on both sides.
• For oxygen ($\ce{O}$): In $\ce{2HNO3}$ there are $2\times3 = 6$ $\ce{O}$ atoms from $\ce{NO3-}$, and $2$ $\ce{O}$ atoms from $\ce{Ba(OH)2}$ (in the $\ce{OH-}$ groups). In $\ce{Ba(NO3)2}$ there are $2\times3 = 6$ $\ce{O}$ atoms from $\ce{NO3-}$, and in $\ce{2H2O}$ there are $2$ $\ce{O}$ atoms.

Answer:

$\ce{2HNO3 + Ba(OH)2->Ba(NO3)2 + 2H2O}$