Question

potassium permanganate reacts with oxalic acid (h2c2o4) & sulfuric acid to form carbon dioxide, water, potassium sulfate & manganese(ii)sulfate. the coefficients in the balanced eq. a 2,5,3,10,8,1,2 b 2,5,3,2,8,10 c 2,2,3,8,1,1 d 2,4,3,2,1,1

Explanation:

Step1: Write un - balanced equation

$KMnO_4 + H_2C_2O_4+H_2SO_4
ightarrow CO_2 + H_2O+K_2SO_4 + MnSO_4$

Step2: Determine oxidation states and electron transfer

In $KMnO_4$, $Mn$ has an oxidation state of +7. In $MnSO_4$, $Mn$ has an oxidation state of +2, so $Mn$ gains 5 electrons. In $H_2C_2O_4$, $C$ has an oxidation state of +3. In $CO_2$, $C$ has an oxidation state of +4, and since there are 2 $C$ atoms in $H_2C_2O_4$, 2 electrons are lost per $H_2C_2O_4$ molecule.

Step3: Balance electrons

To balance the electrons, the ratio of $KMnO_4$ to $H_2C_2O_4$ should be 2:5.

Step4: Balance other elements

After putting 2 for $KMnO_4$ and 5 for $H_2C_2O_4$, balance the remaining elements. We get the balanced equation: $2KMnO_4+5H_2C_2O_4 + 3H_2SO_4=10CO_2 + 8H_2O+K_2SO_4+2MnSO_4$. The coefficients are 2, 5, 3, 10, 8, 1, 2.

Answer:

A. 2,5,3,10,8,1,2