Question

in the phase diagram of water, at high pressure, the solid and liquid boundary shows a positive slope. a true b false

Explanation:

In the phase diagram of water, the solid - liquid boundary typically has a negative slope at low - to - moderate pressures due to the fact that ice is less dense than liquid water. However, at very high pressures, water can form different ice phases. For some of these high - pressure ice phases, the density of the solid (ice) is greater than that of the liquid water. According to the Clapeyron equation \( \frac{dP}{dT}=\frac{\Delta S}{\Delta V} \), when \( \Delta V = V_{liquid}-V_{solid}<0 \) (since \( V_{solid} 0 \) (as melting is an endothermic process with an increase in disorder), the slope \( \frac{dP}{dT}>0 \).

Answer:

a. TRUE