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Question
periodic trends 1. use the following bohr models to answer the questions a - d. (7 points) element x element y a) state the electron configurations for each model above (2pts): x: ____________ y: __________ b) to what family does element x belong? (1pt)________________ c) to what family does element y belong?(1pt) __________________ d) based on the bohr models for element x and element y, which element would you expect to lose an electron (ionization energy) more easily? justify your answer by discussing atomic structure and the elements location on the periodic table. (3pts)
Step1: Determine electron - configurations
For Element X with 11 protons and 11 electrons, the electron - configuration is $1s^{2}2s^{2}2p^{6}3s^{1}$ (using the Aufbau principle to fill orbitals in order of increasing energy). For Element Y with 12 protons and 12 electrons, the electron - configuration is $1s^{2}2s^{2}2p^{6}3s^{2}$.
Step2: Identify element families
Elements in the same family have the same number of valence electrons. Element X has 1 valence electron, so it belongs to the alkali metals family. Element Y has 2 valence electrons, so it belongs to the alkaline - earth metals family.
Step3: Analyze ionization energy
Element X would lose an electron more easily. X is an alkali metal. Its outermost electron is in a 3s orbital and is relatively far from the nucleus compared to inner - shell electrons. Also, it has only 1 valence electron and wants to achieve a stable noble - gas configuration by losing that electron. Y is an alkaline - earth metal and has a filled 3s orbital. Removing an electron from Y requires breaking into a stable electron configuration, so it has a higher ionization energy.
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a) X: $1s^{2}2s^{2}2p^{6}3s^{1}$; Y: $1s^{2}2s^{2}2p^{6}3s^{2}$
b) Alkali metals
c) Alkaline - earth metals
d) Element X. It is an alkali metal with 1 valence electron. Losing this electron gives it a stable noble - gas configuration. Its outermost electron is relatively far from the nucleus and experiences less effective nuclear charge compared to Element Y's outermost electrons.