Question

the percent of college students marijuana use for a sample of 93,818 students is shown in the accompanying pie chart. find the probability of each event listed in parts (a) through (d) below.
click the icon to view the pie chart.
(a) randomly selecting a student who never used marijuana
the probability is 53.3%.
(round to one decimal place as needed.)
(b) randomly selecting a student who used marijuana
the probability is □%.
(round to one decimal place as needed.)

Explanation:

Step1: Use the complement rule

The probability of an event \(A\) and its complement \(\overline{A}\) satisfy \(P(A)=1 - P(\overline{A})\). Let \(A\) be the event of selecting a student who used marijuana and \(\overline{A}\) be the event of selecting a student who never used marijuana.

Step2: Calculate the probability

We know that \(P(\overline{A}) = 53.3\%\). Then \(P(A)=100\% - 53.3\%\)

$$P(A)=46.7\%$$

Answer:

\(46.7\%\)