Question

in part a, we saw that the theoretical yield of aluminum oxide is 1.00 mol. calculate the percent yield if the actual yield of aluminum oxide is 0.780 mol
express your answer with the appropriate units.
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value units

Explanation:

Step1: Recall percent yield formula

Percent yield = $\frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\%$

Step2: Substitute given values

Actual yield = 0.780 mol, Theoretical yield = 1.00 mol
Percent yield = $\frac{0.780}{1.00} \times 100\% = 78.0\%$

Answer:

78.0%