Question

part 1: synthesis reactions

1. _ na + _ o₂ → _ na₂o

4 na + 1 o₂ → 2 na₂o

Explanation:

Step1: Balance sodium atoms

On the right - hand side, there are 2 sodium atoms in \(Na_2O\). Let the coefficient of \(Na\) be \(x\) and the coefficient of \(Na_2O\) be \(y\). For sodium atoms: \(x = 2y\).

Step2: Balance oxygen atoms

On the left - hand side, there are 2 oxygen atoms in \(O_2\), and on the right - hand side, there is 1 oxygen atom in \(Na_2O\). Let the coefficient of \(O_2\) be \(m\) and the coefficient of \(Na_2O\) be \(n\). For oxygen atoms: \(2m=n\).

Step3: Find the coefficients

Let \(n = 2\) (to make the number of oxygen atoms balanced, since if \(n = 2\), then from the oxygen - atom balance \(2m=n\), \(m = 1\)). From the sodium - atom balance \(x = 2y\), when \(y=2\), \(x = 4\).

Answer:

\(4Na+O_2
ightarrow2Na_2O\)