QUESTION IMAGE
Question
part 1 (1 point)
cyclohexanone and cyclohexanol
choose one or more:
a. london dispersion
b. dipole - dipole
c. hydrogen bonding
d. ion - induced dipole
part 2 (1 point)
cyclohexane and cyclopentane
choose one or more:
a. london dispersion
b. dipole - dipole
c. hydrogen bonding
d. ion - induced dipole
Brief Explanations
- Part 1:
- London dispersion (A): All molecules, including cyclohexanone and cyclohexanol, exhibit London dispersion forces as they result from temporary fluctuations in electron distribution.
- Dipole - dipole (B): Cyclohexanone has a carbonyl group (\(C = O\)) which is polar, so it can have dipole - dipole interactions. Cyclohexanol has an \(O - H\) group (also polar due to the electronegativity difference between \(O\) and \(H\)), so it can also have dipole - dipole interactions.
- Hydrogen bonding (C): Cyclohexanol has an \(O - H\) group. Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom (\(O\), \(N\), or \(F\)). In cyclohexanol, the hydrogen attached to oxygen can form hydrogen bonds with the oxygen of another cyclohexanol molecule. Cyclohexanone does not have a hydrogen directly bonded to a highly electronegative atom (the \(C = O\) group's hydrogen is not attached to \(O\)), so it does not have hydrogen bonding.
- Ion - induced dipole (D): There are no ions present in the system of cyclohexanone and cyclohexanol (assuming they are pure substances or in a non - ionic solvent), so this force is not present.
- Part 2:
- London dispersion (A): Cyclohexane and cyclopentane are non - polar hydrocarbons (all \(C - C\) and \(C - H\) bonds, and symmetric enough in their molecular structures for the overall molecule to be non - polar). London dispersion forces are the only intermolecular forces present as they result from the motion of electrons within the molecules.
- Dipole - dipole (B): Since the molecules are non - polar (no significant separation of charge), dipole - dipole forces are absent.
- Hydrogen bonding (C): There are no \(O - H\), \(N - H\), or \(F - H\) bonds in cyclohexane and cyclopentane, so hydrogen bonding does not occur.
- Ion - induced dipole (D): No ions are present (assuming pure hydrocarbons), so this force is not present.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- Part 1: A, B (if considering both substances' general intermolecular force presence; if more specific, cyclohexanone has A and B, cyclohexanol has A, B, and C)
- Part 2: A